(3x ^ 3 + 4x - 1) / (x ^ 2 + 1) คืออะไร

(3x ^ 3 + 4x - 1) / (x ^ 2 + 1) คืออะไร
Anonim

ตอบ:

# 3x + (x-1) / (x ^ 2 + 1) #.

คำอธิบาย:

สังเกตว่า # 3x ^ 3 + 4x-1 #.

# = 3x ^ 3 + 3x + X-1 #, # = 3x (x ^ 2 + 1) + (x-1) #.

#:. (3x ^ 3 + 4x-1) / (x ^ 2 + 1) = {3x (x ^ 2 + 1) + (x-1)} / (x ^ 2 + 1) #, # = {3x (x ^ 2 + 1)} / (x ^ 2 + 1) + (x-1) / (x ^ 2 + 1) #, # rArr (3x ^ 3 + 4x-1) / (x ^ 2 + 1) = 3x + (x-1) / (x ^ 2 + 1) #.