แสดงว่าผิวสีแทน (52.5 °) = sqrt6 - sqrt3 - sqrt2 + 2?

แสดงว่าผิวสีแทน (52.5 °) = sqrt6 - sqrt3 - sqrt2 + 2?
Anonim

# rarrtan75 ° = สีน้ำตาล (45 + 30) #

# = (tan45 + tan30) / (1-tan45 * tan30) #

# = (1 + (1 / sqrt (3))) / (1- (1 / sqrt (3)) #

# = (sqrt (3) +1) / (sqrt (3) -1) = 2 + sqrt (3) #

# rarrtan52.5 = เปล (90-37.5) = cot37.5 #

# rarrcot37.5 = 1 / (สีน้ำตาล (75/2)) #

# rarrtanx = (2tan (x / 2)) / (1-Tan ^ 2 (x / 2)) #

# rarrtanx-Tanx * สีน้ำตาล ^ 2 (x / 2) = 2tan (x / 2) #

# rarrtanx * สีน้ำตาล ^ 2 (x / 2) + 2tan (x / 2) -tanx = 0 #

มันเป็นกำลังสองใน #tan (x / 2) # ดังนั้น, #rarrtan (x / 2) = (- 2 + sqrt (2 ^ 2-4 * * * * * * * * Tanx (- Tanx))) / (2 * Tanx) #

#rarrtan (x / 2) = (- 2 + sqrt (4 (1 + น้ำตาล ^ 2x))) / (2 * Tanx) #

#rarrtan (x / 2) = (- 1 + sqrt (1 + น้ำตาล ^ 2x)) / Tanx #

วาง # x = 75 # เราได้รับ

#rarrtan (75/2) = (- 1 + sqrt (1 + น้ำตาล ^ 2 (75))) / (tan75) #

#rarrtan (75/2) = (- 1 + sqrt (1+ (2 + sqrt (3)) ^ 2)) / (2 + sqrt (3)) #

#rarrtan (75/2) = (- 1 + sqrt (1 + 4 + 4sqrt (3) 3)) / (2 + sqrt (3)) #

#rarrtan (75/2) = (- 1 + sqrt (8 + 4sqrt (3))) / (2 + sqrt (3)) #

# rarr1 / สีน้ำตาล (75/2) = (2 + sqrt (3)) / (2 * sqrt (2 + sqrt (3)) - 1) * (2 * sqrt (2 + sqrt (3)) + 1) / (2 * sqrt (2 + sqrt (3) +1) #

# rarrcot37.5 = (2 * (2 * sqrt (2 + sqrt (3)) + 1) + sqrt (3) * (2 * sqrt (2 + sqrt (3)) + 1)) / ((2 * sqrt (2 + sqrt (3))) ^ 2-1 ^ 2) #

ปล่อย #sqrt (2 + sqrt (3)) = a #

# rarrcot37.5 = (2 * (2 * A + 1) + sqrt (3) * (2 * A + 1)) / ((4 * (2 + sqrt (3))) ^ 2-1) #

# rarrcot37.5 = (4a + 2 + 2sqrt (3) + sqrt (3)) / ((4 * (2 + sqrt (3)) - 1) #

# rarrcot37.5 = (4a + 2sqrt (3) + A ^ 2) / (7 + 4sqrt (3)) * (7-4sqrt (3)) / (7-4sqrt (3)) #

# rarrcot37.5 = 7 * (4a + 2sqrt (3) + a ^ 2) -4sqrt (3) * (4a + 2sqrt (3) + a ^ 2) #

# rarrcot37.5 = 28a + 14sqrt (3) + 7a ^ 2-16sqrt (3)-24a-4sqrt (3) ^ 2 #

# rarrcot37.5 = ^ 7a 2-4sqrt (3) ^ 2 + 4a-2sqrt (3) #

# rarrcot37.5 = a ^ 2 (7-4sqrt (3)) + 2 * (ที่ 2 sqrt (3)) #

# rarrcot37.5 = (2 + sqrt (3)) (7-4sqrt (3)) + 2 * sqrt (2 + sqrt (3)) * sqrt ((2 sqrt (3))) * sqrt ((2 -sqrt (3))) #

# rarrcot37.5 = 2 * (7-4sqrt (3)) + sqrt (3) (7-4sqrt (3)) + sqrt (2 ^ 2 * (2 sqrt (3))) #

# rarrcot37.5 = 14-8sqrt (3) + 7sqrt (3) -12 + sqrt ((sqrt (6) -sqrt (2)) ^ 2) #

# rarrtan52.5 = 2 sqrt (3) + sqrt (6) -sqrt (2) #

ได้รับการพิสูจน์

ตอบ:

แนวทางที่เล็กกว่า …

กฎที่ใช้: -

#color (สีแดง) (ul (แถบ (| สี (สีเขียว)) (sin2theta = 2 cdot sintheta cdot costheta)) | #

# cos2theta = ^ 2cos 2theta-1 #

# => สี (สีแดง) (UL (บาร์ (| สี (สีฟ้า) (2cos ^ 2theta = 1 + cos2theta)) | #

คำอธิบาย:

#tan (52.5 ^ @) #

# = sin (52.5 ^ @) / cos (52.5 ^ @) #

# = sin (105/2) ^ @ / cos (105/2) ^ @ #

# = (2 cdot sin (105/2) ^ @ cdot cos (105/2) ^ @) / (2 cdot cos (105/2) ^ @ cdot cos (105/2) ^ @ #

# = sin (105/2 xx2) ^ @ / (2 cdot cos ^ 2 (105/2) ^ @ #

# = sin (105) ^ @ / (cos (105) ^ @ + 1) #

# = sin (60 ^ @ + 45 ^ @) / (cos (60 ^ @ + 45 ^ @) + 1) #

# = (sin60 ^ @ cdot cos45 ^ @ + cos60 ^ @ cdot sin45 ^ @) / (cos60 ^ @ cdot cos45 ^ @ -sin60 ^ @ cdot sin45 ^ @ + 1 #

# = (sqrt3 / 2 cdot 1 / sqrt2 + 1/2 cdot 1 / sqrt2) / (1/2 cdot 1 / sqrt2-sqrt3 / 2 cdot 1 / sqrt2 + 1 #

# = ((sqrt3 + 1) / (2sqrt2)) / ((1 + sqrt3 2sqrt2) / (2sqrt2) #

# = (sqrt3 + 1) / (1-sqrt3 + 2sqrt2 #

# = ((sqrt3 + 1) cdot (1 + 2sqrt2 + sqrt3)) / ((1 + 2sqrt2) ^ 2- (sqrt3) ^ 2) #

# = (sqrt3 + 2sqrt6 + 3 + 1 + + 2sqrt2 sqrt3) / (1 + 4sqrt2 + 8-3) #

# = (2 (sqrt6 + + sqrt3 sqrt2 + 2)) / (6 + 4sqrt2) #

# = ((sqrt6 + + sqrt3 sqrt2 + 2)) / (3 + 2sqrt2) #

# = ((3-2sqrt2) (sqrt6 + + sqrt3 sqrt2 + 2)) / ((3 + 2sqrt2) (3-2sqrt2) #

# = (sqrt6-sqrt3-sqrt2 + 2) / 1 #

# = sqrt6-sqrt3-sqrt2 + 2 #

หวังว่ามันจะช่วย …

ขอบคุณ…

# tan105 ^ @ = สีน้ำตาล (60 ^ @ + 45 ^ @) #

# => tan105 ^ @ = (tan60 ^ @ + tan45 ^ @) / (1-tan60 ^ @ tan45 ^ @) #

# => tan105 ^ @ = (sqrt3 + 1) / (1-sqrt3 * 1) #

# => tan105 ^ @ = (1 + sqrt3) / (1-sqrt3) #

# => tan105 ^ @ = - ((sqrt3 + 1) (sqrt3-1)) / (sqrt3-1) ^ 2 #

# => tan105 ^ @ = - (3-1) / (4-2sqrt3) #

# => (2tan52.5 ^ @) / (1-tan ^ 2 52.5 ^ @) = - 1 / (2-sqrt3) #

ปล่อย #tan52.5^@=x#

ตอนนี้

# (2x) / (1-x ^ 2) = - 1 / (2 sqrt3) #

# => x ^ 2-2 (2 sqrt3) x-1 = 0 #

# => x = (2 (2 sqrt3) + sqrt (4 (2 sqrt3) ^ 2 + 4)) / 2 #

เช่น #52.5^@in "First Quadrant -ve root ได้รับการละเลย" #

# => x = (2 (2 sqrt3) + 2sqrt ((2 sqrt3) ^ 2 + 1)) / 2 #

# => x = (2 sqrt3) + sqrt ((2 sqrt3) ^ 2 + 1) #

# => x = (2 sqrt3) + sqrt (8-4sqrt3) #

# => x = (2 sqrt3) + sqrt (2 (4-2sqrt3) #

# => x = (2 sqrt3) + sqrt (2 (sqrt3-1) ^ 2) #

# => = x 2 + sqrt3 sqrt2 (sqrt3-1) #

# => = x 2 + sqrt3 sqrt6-sqrt2 #

# => x = sqrt6-sqrt3-sqrt2 + 2 #