คุณแบ่งอย่างไร (-6x ^ 4-3x ^ 3-2x ^ 2-4x-7) / (x ^ 2 + 3)

คุณแบ่งอย่างไร (-6x ^ 4-3x ^ 3-2x ^ 2-4x-7) / (x ^ 2 + 3)
Anonim

ตอบ:

#COLOR (สีฟ้า) ((- 6x ^ 4-3x ^ 3-2x ^ 2-4x-7) / (x ^ 2 + 3) = - 6x ^ 2-3x + 16 + (5x-55) / (x ^ 2 + 3)) #

คำอธิบาย:

# (- 6x ^ 4-3x ^ 3-2x ^ 2-4x-7) / (x ^ 2 + 3) #

วิธีการส่วนยาว:

# "" "" "" "" "" ขีดเส้นใต้ (-6x ^ 2-3x + 16 "" "" "" "" "" "" "" "" ") ที่ # #

# x ^ 2 + 0 * x + 3 | ~ -6x ^ 4-3x ^ 3-2x ^ 2-4x-7 #

# "" "" "" "" "" ขีดเส้นใต้ (-6x ^ 4 + 0 * x ^ 3-18x ^ 2 "" "" "" ") #

# "" "" "" "" "" "" "-3x ^ 3 + 16x ^ 2-4x-7 #

# "" "" "" "" "" "" "" ขีดเส้นใต้ (-3x ^ 3 + 0 * x ^ 2-9x) #

# "" "" "" "" "" "" "" "" 16x ^ 2 + 5x-7 #

# "" "" "" "" "" "" "" "" "" ขีดเส้นใต้ (16x ^ 2 + 0 * x + 48) #

# "" "" "" "" "" "" "" "" "" "" "" "" "+ 5x-55 larr #เหลือ

คำตอบ

#COLOR (สีฟ้า) ((- 6x ^ 4-3x ^ 3-2x ^ 2-4x-7) / (x ^ 2 + 3) = - 6x ^ 2-3x + 16 + (5x-55) / (x ^ 2 + 3)) #